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5x+7*2x^2-4=0
Wy multiply elements
14x^2+5x-4=0
a = 14; b = 5; c = -4;
Δ = b2-4ac
Δ = 52-4·14·(-4)
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{249}}{2*14}=\frac{-5-\sqrt{249}}{28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{249}}{2*14}=\frac{-5+\sqrt{249}}{28} $
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